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In an ap s5+s7 167

WebApr 12, 2024 · In an AP, If S5 + S7 = 167 and S10 = 235 then find the AP, where Sn - YouTube In this video i solved important questions of class 10 maths for term 2,the question is as followingIn an AP,... WebIn an AP, S5 + S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms urgently need this answer!!!! - Maths - Arithmetic Progressions

In an AP, if S5 + S7 = 167 and S10 = 235 , then find the …

WebIn an AP. It is given that S5 + S7 = 167 and S10 = 235 , then find the AP, where Sn denotes the sum of its first n terms In an AP. It is given that S5 + S7 = 167 and S10 = 235 , then find the AP, where Sn denotes the sum of its first n terms Arithmetic Progression CBSE Class 10 Maths RS Aggarwal In an AP. trew hud download https://tuttlefilms.com

In an A.P., S5 + S7 = 167 and S10 = 235, then find the A.P., …

WebMay 29, 2024 · in an AP ;if S5+S7=167 and S10=235 then find the AP ; where Sn denote the sum of its first n terms ANSWER: let a and b be the first term common difference of the AP,respectively therefore ,sum of n terms ,Sn =n/2 (2a+ (n-1)d) we have S5+S7=167 ⇒ 5/2 (2a+4d)+7/2 (2a+6d)=167 ⇒ 5 (a+2d)+7 (a+3d)=167 ⇒ 12a+31d=167 ----- (1) also, S10=235 WebAug 20, 2024 · In an AP, it is given that \( S_{5}+S_{7}=167 \) and \( S_{10}=235 \), then find the AP, where \( S_{n} \) denotes the sum of its first \( n \) terms.W📲PW A... In an AP, it is … WebIt is given that S5 + S7 = 167 and S10 = 235 , then find the AP, where Sn denotes the sum of its first n terms. Arithmetic Progression CBSE Class 10 Maths RS Aggarwal. In an AP. … trew house bude

In an AP, if S5 + S7 = 167 and S10 = 235, then find the AP, where …

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In an ap s5+s7 167

In an A.P., if S5 + S7 = 167 and S10=235, then find the A.P., where …

WebIn an A.P., if S5 + S7 = 167 and S 10= 235, then find the A.P., where Sn denotes the sum of its first n terms. Advertisement Remove all ads Solution S S and S S 5 + S 7 = 167 and S 10 = … WebIn an AP if S5+S7 =167 and S10 =235 then find S6. Class 10 cbse AP extra questions RR Maths Mantra 5 subscribers Subscribe 37 views 10 months ago #cbseclass10 …

In an ap s5+s7 167

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WebFeb 1, 2024 · In an AP. It is given that S5 + S7 = 167 and S10 = 235 , then find the AP, where Sn denotes the sum of its first n terms. asked Sep 14, 2024 in Mathematics by Mubarak (32.9k points) arithmetic progression; class-10; Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to ... WebIn an AP, if S 5 + S 7 = 167 and S 10 = 235, then find the AP, where S n denotes the sum of its first n terms.

WebJul 9, 2024 · closed Jul 10, 2024 by Anaswara In an AP. It is given that S5 + S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms. arithmetic progression class-10 1 Answer +2 votes answered Jul 9, 2024 by Dheeya (31.0k points) selected Jul 10, 2024 by Anaswara Best answer WebMar 19, 2024 · In an AP, if S5+S7 =167 and S10=235, then find the AP, where Sn denotes the sum of its first n terms. 15. Let a be the flrst term and d be the common तilt of: the given …

WebNov 30, 2024 · In an AP, if S5 +S7 =167 and S10 =235, then find the AP, where Sn denotes the sum of its first n terms. [2015] ...[2M] Corporate Off. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ... WebJan 19, 2024 · 14K views 3 years ago Arithmetic Progressions In an AP, if S5 + S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms. Show more The …

Web>> In an A.P., S5 + S7 = 167 and S10 = 2. ... Verified by Toppr. Was this answer helpful? 0. 0. Similar questions. If the 3rd and the 9th terms of an AP are 4 and -8 respectively. which term of this AP IS ZERO ? Medium. View solution > If the sum of 7 terms of an A.P is 4 9 and that of 1 7 terms is 2 8 9, find the sum of n terms.

WebJan 24, 2024 · Step-by-step explanation: Answer We know that sum of n terms sn = n/2 (2a + (n - 1) * d) Given s5 + s7 = 167. = 5/2 (2a + (5 - 1) * d) + 7/2 (2a + (7 - 1) d) = 167 = 5/2 (2a + 4d) + 7/2 (2a + 6d) = 167 = 5 (a + 2d) + 7 (a + 3d) = 167 = 5a + 10d + 7a + 21d = 167 = 12a + 31d = 167 ---------- (1) Given that s10 = 235 10/2 (2a + (10 - 1) * d) = 235 tenglang whut.edu.cnWebIn an AP, it is given that S 5 + S 7 = 167 a n d S 10 = 235, then find the AP, where S n denotes the sum of its first n terms. Q. In an AP, if S 5 + S 7 = 167 and S 10 = 235 , then find the … trewick labWebFeb 13, 2016 · In an AP, if S5 + S7 = 167 and S10 = 235, then find the A P , where Sn denotes the sum of its first n term - Maths - Arithmetic Progressions NCERT Solutions Board Paper … teng lay import export \u0026 transport co. ltdWebIn an AP. It is given that S 5 + S 7 = 167 and S 10 = 235 , then find the AP, where S n denotes the sum of its first n terms. arithmetic progression class-10 1 Answer +1 vote answered … tengle information technology co. ltdWebLet a and d be the first term and the common difference of the AP, respectively Chapter Chosen. Arithmetic Progressions Book Chosen. Mathematics Subject Chosen. Mathematics ... In an AP, if S 5 + S 7 = 167 and S 10 = 235, then find the AP, Where S n denotes the sum of its first n terms. Let a and d be the first term and the common difference of ... teng lab baylor college of medicineWebJun 19, 2024 · The sum of first 5 terms of an ap and the sum of first 7 terms of an ap is 167 if sum of first 10 terms of the ap is 235 find the sum of its first 20 terms Advertisement pradu4321 is waiting for your help. … trewick lillethWebJan 2, 2024 · thesarcasticsoul Answer: S5+S7=5/2(2a+4d) +7/2(2a+6d)=167 =5a+10d+7a+21d=167 =12a+31d=167 [let this be eqn 1] similarly, from S10=235, we get 2a+9d=47 {let this be equation 2} by solving eqn 1 and 2, we get a=1 and d=5 therefore the ap is 1,6,11........ Step-by-step explanation: Advertisement Advertisement New questions in … ten glees madrigals and airs 楽譜